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help please :) solve for x log3 9 =x. (the three is lower than the log )
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you need to use your calculator for this one \[\log_3 (9) = \frac{ \log_{10}(9) }{ \log3 }\]
cool thanks
i meant to write this\[\log_3(9) = \frac{ \log_{10}(9) }{ \log_{10}(3) }\]
just one question where did the 10 come from?
the log button on your calculator is log base 10. this also works if you use the ln button, which is log base e, aka the natural logarithm
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ohhhhhhhhh coolies thankyouu
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