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Mathematics 13 Online
OpenStudy (anonymous):

|x+1|≤|x-3|

OpenStudy (watchmath):

try to square both sides

OpenStudy (watchmath):

remember that \(|x|^2=x^2\)

OpenStudy (anonymous):

uh?

OpenStudy (watchmath):

I mean if you square both sides you have \[\Large (x+1)^2\leq(x-3)^2 \]

OpenStudy (watchmath):

expand, simplify and continue from there

OpenStudy (anonymous):

why will it be squared?

OpenStudy (watchmath):

so we can get rid off the absolute value sign

OpenStudy (anonymous):

uh? we wont multiply it by -?

OpenStudy (watchmath):

sorry, I mean to get rid of the absolute value symbol

OpenStudy (anonymous):

i see. okay2..

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