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Mathematics 15 Online
OpenStudy (anonymous):

y=tanx dx/dt=2 x=-3.14/3 dy/dt=?

OpenStudy (solomonzelman):

@wio

OpenStudy (anonymous):

\[y = \tan x\] \[\frac{dy}{dt} = \sec^2 x \frac{dx}{dt}\]

OpenStudy (anonymous):

then would the answer be 8

OpenStudy (anonymous):

I think so!

OpenStudy (anonymous):

thanks

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