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OpenStudy (anonymous):
Tell me please how the process d^2 / (dt)^2 (AxB)?
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OpenStudy (anonymous):
m not able to undrstand ur question.
OpenStudy (anonymous):
The second derivative (AxB) I mean
OpenStudy (amistre64):
are A and B matrixes?
OpenStudy (anonymous):
no, it isn't
OpenStudy (amistre64):
then you might want to provide more context for the question
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OpenStudy (anonymous):
do u mean double differentiation of [u*v] form?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
firts differentiation will be, |dw:1381838724689:dw|
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