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Algebra
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(2x+5)^2-(2x+5)-6=0
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notice is just a quadratic in disguise
if the question was x^2 - x - 6 = 0 what would you get?
i understand how to do it, but i want to see if i get the right answer
so what answer did you get?
so far: 4x^2+18x+24
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hmm.. I don't see how you got that nor how it factors out or works... :/ here, could you first find x when: x^2 - x - 6 = 0
x= -2 and 3
yes, and in that case I had substitute (2x+5) for x temporarily so if x = 2x + 5 so solve for x when 2x + 5 = -2 and 2x + 5 = 3
x=\[\frac{ -7 }{ 5 }\] and -1
i meant over 2
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not 5
yes :) so those are your answers for (2x+5)^2-(2x+5)-6=0
ohhhh, i see what you did there
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