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Write the quadratic function in vertex form. Then identify the vertex... y= x^- 12x+1
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Take 1/2 of (-12) and square it ...completing the square S0, y = (x-6)^2 - 35
okay I dont get this one y= -2x^ +8x-3
@Mertsj
\[y=-2(x^2-4x ) -3\] \[y=-2(x^2-4x+4)-3+8\] \[y=-2(x-2)^2+5\]
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