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Mathematics 6 Online
OpenStudy (anonymous):

Factor completely: 2x3 + 14x2 + 6x + 42 2[(x2 + 3)(x + 7)] (2x2 + 6)(x + 7) (x2 + 3)(2x + 14) 2(x3 + 7x2 + 3x + 21)

jigglypuff314 (jigglypuff314):

can factor out 2 so 2x3 + 14x2 + 6x + 42 = 2(x^3+7x^2+3x+21)

OpenStudy (anonymous):

So D.

jigglypuff314 (jigglypuff314):

yes :)

OpenStudy (anonymous):

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