Question

hey find the points of inflection on f(x)=6x^4-x^2
thanksss

oh and i got plus or minus 1/6

Answer 1

was that not correct?

Answer 2

f'(x) = 24x^3 - 2x

f''(x) = 72x^2 - 2

set f''(x) = 0...you get 2(36x^2 - 1) = 0, or x = +1/6 and -1/6

Now, set up an interval chart to see where concavity, if any, exists.

Answer 3

ok

Answer 4

do you plug in the number to the first der. ?

Answer 5

to check for concavity