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Mathematics 16 Online
OpenStudy (anonymous):

Find the mean of the discrete random variable with the probability distribution below. x 5 9 12 14 19 P(x) 0.2 0.15 0.1 0.3 0.25

OpenStudy (anonymous):

have you been introduced to 'weighted averages'

OpenStudy (anonymous):

if so I can help, if not i can still help, but the method might not be what your professor wants you to do

OpenStudy (anonymous):

E[X] = 5(.2) + 9(.15) + 12(.1) + 14(.3) + 19(.25) = 12.5

OpenStudy (anonymous):

nicely done!, but you are missing one part.. \[\frac{ 5(.2) + 9(.15) + 12(.1) + 14(.3) + 19(.25) }{ .2 + .15 + .1 + .3 + .25}\]

OpenStudy (anonymous):

make sense?

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