Question

find the linearization L(x) of the function at a.
f(x)=sin x, a=pi/6

Answer 1

This is normally the same as finding the tangent line at pi/6

y = f(a) + f'(a)*(x-a)

y = 1/2 + sqrt3/2(x-pi/6)

y = sqrt3/2 x + (6-pi*sqrt3)/12

Answer 2

where does the sqrt3 come from?