Question

Show that 2-i and -2+i are square roots of 3-4i.

Answer 1

let the square root of 3-4i be a+bi
so, we have \(\large a+bi=\sqrt{3-4i}\)
square both sides of this equation, what do u get ?

Answer 2

\[a ^{2} + bi ^{2} = 3-4i ??\]

Answer 3

\[(f+g)^2 ≠ f^2 +g^2\]

\[(f+g)^2 = f^2 + 2fg +g^2\]