Question

is this correct ?
what are the solutions ?
16x^2+9=0

A. -3/4i,3/4i
B. -4/3i,4/3i
C. -3/4, 3/4 <----- my answer
D. -9/16i,9/16i

Answer 1

if you plug those back in for x do you get the original problem back?

Answer 2

what do you mean ?

Answer 3

maybe it would be better if I asked you how you got that answer

Answer 4

16x^2-9=0
(4x+3)(4x-3)=0
4x+3=0; 4x-3=0
4x=-3; 4x=3
x=-3/4; x=3/4

Answer 5

try subtracting 9 from each side and then taking the square root of each side. What do you get?

Answer 6

your original problem says 16x^2+9 not -9,
which is correct?

Answer 7

oh lol my bad