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Mathematics 9 Online
OpenStudy (anonymous):

h

ganeshie8 (ganeshie8):

use quadratic formula

ganeshie8 (ganeshie8):

\(\large x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\)

ganeshie8 (ganeshie8):

you did it correct, except for a minor mistake..

ganeshie8 (ganeshie8):

-b it is in the quadratic formula, so u shud get, \(\large x= \frac{\color{red}{-}1 \pm i \sqrt{15}}{4} \)

ganeshie8 (ganeshie8):

otherwise, its a good job !

ganeshie8 (ganeshie8):

np :)

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