Question

integrate sinx/cos^2x

Answer 1

\[\frac{\text{Sin}[x]}{\text{Cos}[x]^2}=\text{Sec}[x] \text{Tan}[x] \]\[\int\limits \text{Sec}[x] \text{Tan}[x]dx=\text{Sec}[x] \]

Answer 2

where did u get the sec tan from at the begginig how did u get that