The axis intercepts and the vertex of the curve y=x^2-12x+20 form the corners of a quadrilateral. I need to calculate the area..

Question

campbell_st · Answer

i'd find the intercepts and vertex and determine the type of quadrilateral

ok... so what are the intercepts

y-interscept let x = 0 and solve for y

x- intercepts  let y = 0 and solve

$$x^2 - 12x + 20 = 0$$

the vertex

find the line of symmetry 

x = -b/2a            in your question b = -12 and a = 1

then substitute this value to into the equation to find the vertex... 

plot the points... 

then work from there...

anonymous · Answer

cheers!