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HELPP!!! will give medal :) Given parallelogram EFGH with perimeter 58, solve for EF EG and EH
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@agent0smith
@RadEn
@jdoe0001
I kno I have to find x but idk how I though I had the right idea but it was wrong
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x+x+x+3+x+3 = 58 combine the similar terms, then solve for x
4x+6=58 4x=52 x=13
yes, you are right!
Ok thanks I think I got it from here :)
so, EF = x = 13 EG = 2x = 2 *13 = 26 EH = x+3 = 13+3 = 16 wlcm
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