Question

In the below system, solve for y in the first equation.

2x + y = 11
5x - 2y = -1

2x + 11
-2x + 11
2x - 11
-2x - 11
2. In the below system, solve for y in the first equation.

x + 3y = 6
2x - y = 10

one thirdx + 2
negative one thirdx + 6
-x + 2
negative one thirdx + 2
3. What is the value of y in the solution to the following system of equations?

5x - 3y = -3
2x - 6y = -6

-1
zero
1
2
4. Use the substitution method to solve the following system of equations.

3x + 5y = 3
x + 2y = 0

(1, 1)
(6, -3)
(6, 1)
(1, -3)
PLEASE HELP!!!!!

Answer 1

Not trying to be rude, but there is a thing called your brain. If you just read the question and work out the problem I bet you anything you'll get it right. :) If you don't then post your work and then someone can help you correct your mistakes. Not just baby you and give you the answer.

Answer 2

pLEASE BABY ME

Answer 3

Idk, nor do I care to know, I just really need the answers.

Answer 4

That's the problem, you don't care. So why should anyone
help someone who doesn't actually care?

Answer 5

I do care, about my grade :P

Answer 6

Well, I'm not going to help you unless you show effort and actually try. Best of luck to you.

Answer 7

Do you even know yourself?

Answer 8

Actually I do know myself. I try and then I ask. I don't just straight up cheat.