7 + (-3x2) for x = 0.

Question

anonymous · Answer

distribut first

anonymous · Answer

the 2 is a power btw.

goldphenoix · Answer

Or you can just replace. 

7 + [-3(0)^2]

♪chibiterasu · Answer

Indeed. x being 0 leaves everything in the parenthesis being equivalent to 0 so now we have:

7 + (0)

Which is obviously just 7.

anonymous · Answer

a positve times a negitive is a positive right?

♪chibiterasu · Answer

No, positive times positive is negative, and negative times negative is positive. It gets confusing so don't feel bad :3

♪chibiterasu · Answer

positive times negative is negative sorry

♪chibiterasu · Answer

Typo >.>

goldphenoix · Answer

Chibi is right. Anyway, let me explain in more detail.
[-3(0)^2]
You do exponent first, since order of operation say so. 
0^2 can be written as 0 * 0. 0 * 0 = 0. (That's a lot of zero')
Now you have [-3*0]. And we all know that anything multiply by zero is zero.
So now you have 7 + [0].
7 + 0 is 7.