Question

In the below system, solve for y in the first equation.

2x + y = 11
5x - 2y = -1

2x + 11
-2x + 11
2x - 11
-2x - 11
2. In the below system, solve for y in the first equation.

x + 3y = 6
2x - y = 10

one thirdx + 2
negative one thirdx + 6
-x + 2
negative one thirdx + 2
3. What is the value of y in the solution to the following system of equations?

5x - 3y = -3
2x - 6y = -6

-1
zero
1
2
4. Use the substitution method to solve the following system of equations.

3x + 5y = 3
x + 2y = 0

(1, 1)
(6, -3)
(6, 1)
(1, -3)
PLEASE HELP!!!!!