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Solve |4x – 10| + 2 ≤ 8
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1≤x≤4
this is a an inequality right?
if so its \[1\le x \le4\]
\(\bf |4x - 10| + 2 \le 8\implies |4x - 10| \le 8-2\implies |4x - 10| \le 6\\ \quad \\ |4x - 10| \le 6\implies \begin{cases} +(4x - 10) \le 6\\ \quad \\ \bf -(4x - 10) \le 6 \end{cases}\)
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