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which values of x and y will make the expression 5(x-y)2 equal to 20?
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hint: let z = x-y replace "x-y" with z, then solve for z
\[5(x-y)^{2} equal \to 20\]
so is x-y/z
5(x-y)^2 = 20 5z^2 = 20 z^2 = 20/5 z^2 = 4 z = ???
z=8
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no
z^2 means z squared
i don't know
if z^2 = 4, then z = 2 or z = -2 so if z = x-y, then x-y = 2 or x-y = -2
from there, you can solve each equation for y to get it in terms of x
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