Question

A bacteria culture starts with 1000 bacteria and the population triples after 3 hours. Find an expression for the number y(t) of bacteria after t hours.

What I have so far is: y(t)=1000e^(?)

Answer 1

in not familiar with this type of problem, but go to http://answers.yahoo.com/question/index?qid=20101014073636AAw0Trf
site. it has an example to ur question

Answer 2

I was looking at the same problem earlier and I thought I had the answer but it kept saying it was wrong. So I thought I typed in wrong and tried different ways of typing it but it didn't work. So I was hoping I could figure out the answer to see if I was completely wrong or wrote in wrong.

Answer 3

that problem is after 6 hours, urs is after 3 hours.. did u change the time

Answer 4

yes

Answer 5

y(t) = 1000*e^((ln(3)/3)*t)
did u put it like that?

Answer 6

Ah thank you! It was a typo on how I put it in.

Answer 7

How's this?
0 hours population = 1,000
3 hours population = 3,000
6 hours population = 9,000

So population = 1,000*3^(t/3)

0 hours = 1,000*3^0 =
1,000^1 = 1,000

3 hours = 1,000*3^(t/3)
3 hours = 1,000*3^1 = 1,000 * 3 = 3,000

6 hours = 1,000*3^(t/3)
6 hours = 1,000*3^(6/3)
6 hours = 1,000*3^(2)
= 1,000*3² = 9,000

Answer 8

welcome :)