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The cost, C, in dollars, of fuel per month for Sanjay to operate his truck is given by C(v) = 0.0029v^2 - 0.48v +142, where v represents his average driving speed, in kilometres per hour. Find the most efficient speed at which Sanjay should drive his truck.
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First step that you have to do is to minimize the C in the equation. C(v)=0.0058v -0.48=0 v=0.48/0.0058 v=82.75862069 km/hr You cold also use a graph to find out that axis of sym is on 82.7 as well as the vertex.
I take it this is a calculus question. anytime you want to 'maximize' or make anything 'efficient' in a math class, what it's really saying for you to do is to take the derivative and set it equal to zero, then solve for v (v for our case, but normally it's x).
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