Question

Can someone teach me how to Solve Algebraic Proportions?

Answer 1

Do you have a problem in mind?

Answer 2

direct proportions or inverse proportions ?

Answer 3

I think he means proportions like\[\frac{ x }{ y } = \frac{ a }{ b }\]

Answer 4

Solve for x in the proportion 3 over the quantity x plus 2 equals 6 over the quantity x minus 1.

x = −5

x = 1

x = 4

x = 5

Answer 5

@Grazes

Answer 6

3/(x + 2) = 6/(x - 1)
do you know how to cross multiply ?

Answer 7

Not really.

Answer 8

take the numerator of one and multiply it by the denominator of the other and vice versa.

3/(x + 2) = 6/(x - 1)
numerator of one x denominator of the other
3(x - 1) = 6(x + 2)

can you understand how I did that ?