Can someone teach me how to Solve Algebraic Proportions?

Question

anonymous · Answer

Do you have a problem in mind?

texaschic101 · Answer

direct proportions or inverse proportions ?

anonymous · Answer

I think he means proportions like$$\frac{ x }{ y } = \frac{ a }{ b }$$

anonymous · Answer

Solve for x in the proportion 3 over the quantity x plus 2 equals 6 over the quantity x minus 1.

 x = −5

 x = 1

 x = 4

 x = 5

anonymous · Answer

@Grazes

texaschic101 · Answer

3/(x + 2) = 6/(x - 1)
do you know how to cross multiply ?

anonymous · Answer

Not really.

texaschic101 · Answer

take the numerator of one and multiply it by the denominator of the other and vice versa.

3/(x + 2) = 6/(x - 1)
numerator of one x denominator of the other
3(x - 1) = 6(x + 2)

can you understand how I did that ?

anonymous · Answer

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