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what is the area of the parallelogram 40, 68 and 150 degrees
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The area of a parallelogram is given with the formulae of A=b*h.
I Know but I don't know how to resolve the problem
Use the formula , Area of parallelogram = ab sin C...that is two adjacent sides multiplied by the sine of the included angle. So, Area = 40(68) sin (150) = 40(68)(1/2) 1,360
Honestly, I cannot understand what you are asking me. Perhaps rephrase what you are asking.
How do you get 1,360
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40 x 68 x sin 150 degrees
put it on your calculator
got it?
thank you so much! now I'm ready for the SPAT
Good Luck.
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You mean PSAT
Thanks
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