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Use the given function value(s) and the trigonometric identities to find the indicated trigonometric functions. tan β = 5 (a) cot β (b) cos β (c) tan(90°-β) (d) csc β
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|dw:1381890544171:dw|
cot B = 1/5
cos B = 1/sqrt(26)
(b) i got sq rt(26)/26
csc B = sqrt(26)/5
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tan (90 - B) = 1/5
sqrt(26)/26 = 1/sqrt(26)
oh so its the same?
Never mind i understand now. thanks!
they are the same..if you rationalize the denominator of 1/sqrt(26) you get sqrt(26)/26
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Oh by the way for (d) i got 5 sqrt (26)/ 26.
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