Mathematics
14 Online
OpenStudy (anonymous):
Suppose U = {1,2,3,4,5,6,7,8,9,10} is the universal set and Q = {3,6,9} What is Q?
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OpenStudy (anonymous):
What is Q? Well they gave it. Do they want Q or Q compliment?
OpenStudy (anonymous):
Q compliment
OpenStudy (anonymous):
Just take all the numbers in U set that aren't in Q set.
OpenStudy (anonymous):
You can do it.
OpenStudy (anonymous):
Still confused?
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OpenStudy (anonymous):
Very much so
OpenStudy (anonymous):
Oh! I understand!
OpenStudy (anonymous):
Good luck!
OpenStudy (anonymous):
So, wait, would it be 1,4,5,7,8,9,10 etc?
OpenStudy (anonymous):
@wio
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OpenStudy (anonymous):
Not quite, let me show.
OpenStudy (anonymous):
\[
\overline{Q}= U-Q= \{1,2,\cancel3,4,5,\cancel6,7,8,\cancel9,10\} - \{\cancel3,\cancel6,\cancel9\} = \{1,2,4,5,10\}
\]
OpenStudy (anonymous):
Ahh, okay. Thank you @wio I have one more question for you
OpenStudy (anonymous):
Sure.
OpenStudy (anonymous):
Suppose U = {1,2,3,4,5,6,7,8} and A = {1,3,5,7} and B = {4,5,6}
A subset B
True or False?
B subset U
True or False?
@wio
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OpenStudy (anonymous):
Well, if A is a subset of B, then \(A-B=\emptyset=\{\}\)
OpenStudy (anonymous):
So you can use set different to tell.
OpenStudy (anonymous):
I'm confused.
OpenStudy (anonymous):
@wio
OpenStudy (anonymous):
Do you know what a subset is?
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OpenStudy (anonymous):
To be honest, no.
OpenStudy (anonymous):
That is the problem, you need to understand it.
If A is a subset of B, for example, that means that every element in A is also in B
OpenStudy (anonymous):
Oh, okay, so then A subset B is false
OpenStudy (anonymous):
@wio
OpenStudy (anonymous):
Yeah, it is false.
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OpenStudy (anonymous):
But, B subset U isn't because {4,5,6} are all in {1,2,3,4,5,6,7} @wio
OpenStudy (anonymous):
Correct?
OpenStudy (anonymous):
B is a subset of U
OpenStudy (anonymous):
Thank you!