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Mathematics 7 Online
OpenStudy (anonymous):

Ok... I just want to know if I'm on the right track. My problem is (x+5)(x-3)(4x-5). Now.. I separated the first two and got x^2+3x+5x-15. Now, am i suppose to do (x^2+3x+5x-15)(4x-5) or did i mess up somewhere.

Directrix (directrix):

(x+5) *(x-3) = x² +2x - 15. So, (x+5)(x-3)(4x-5) = (x² +2x - 15) * ((4x-5). You have another multiplication to do. @Sphinxkitty

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