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show that x^3 cosnx is an odd function and x^3sinnx is an even ∫_π^π▒〖x^3 cosnxdx〗someone help please
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@phillemon in case of "cos" function put x=(-x) ,you will get x^3=-x^3& cosnx=cosnx. so,f(x)=-f(-x),hence x^3cosnx is an "odd" function. while after putting -x at the place of x, you will get x^3=-x^3 & sinnx=-sinnx. so you get f(x)=f(-x),hence x^3sinnx is an "even" function
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