Question

Write the equation of a line that has a slope of -4/3 and passes through the point (3, -2)

Answer 1

to find the equation of a line in slope-intercept form y = mx + b
plug in what you know when m = slope = -4/3 and (x,y) = (3, -2)
so y = mx + b
(-2)= (-4/3)(3) + b find b

then plug the number you found b to be back into the y = mx + b
so y = (-4/3)x + (b)

Answer 2

so y=-4/3x+6 is the answer

Answer 3

to find b
(-2)= (-4/3)(3) + b multiply
-2 = -4 + b then add 4 on both sides
+4 +4
-2 + 4 = b

Answer 4

what?