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What is the remainder when 4^31 is divided by 10?
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what doe the division give you?
that is \(\bf 4^{31} \div 10\)
so it would be 4
well... no , you grab the integer part, the non-decimal one, and multiply by 10 whatever that gives you, subtract THAT AMOUNT from \(\bf 4^{31}\) and that will be the remainder
\(\bf 4^{31}\div 10 = \color{red}{461168601842738790}.4\\ \quad \\ 10 \cdot \color{red}{461168601842738790} \implies \color{blue}{4611686018427387900}\\ \quad \\ 4^{31}\implies 4611686018427387904\qquad thus\\ \quad \\ 4611686018427387904 \quad -\quad \color{blue}{4611686018427387900} \implies remainder\)
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