Question

ok

Answer 1

\[6\sqrt{x + 1} - 3 = 15\]\[6\sqrt{x+1} = 18\]\[\frac{6\sqrt{x+1}}{6} = \frac{18}{6}\]\[\sqrt{x+1} = 3\]\[\sqrt{x+1}^2 = 3^2\]\[x + 1 = 9\]\[x = 8\]