A train goes up a hill with a 15º incline. If the train has constant speed of 22 m/s, what are the vertical and horizontal components of the train's velocity? (Remember to use the law of sine and cosines for this problem)

Question

anonymous · Answer

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remember that sin() = opposite/ hypotenuse, so 
sin(15) = V_y / 22
so times both sides by 22 and it looks like this now
22* sin(15) = V_y

can you find V_x know that cos() = adjacent/hypotenuse