Question

perform the operation and write it in standard form. Please help!
(i/3-2i)+(2i/3+8i)

Answer 1

Just add normally.

Answer 2

i would write both in standard form first, then add
\[\frac{i}{3-2i}=\frac{i}{3-2i}\times \frac{3+2i}{3+2i}=\frac{-2+3i}{9+4}=\frac{-2}{13}+\frac{3}{13}i\]

Answer 3

It looks different in the prompt. Which one is it? i/(a+bi) or i/a+bi?

Answer 4

you have to do the same thing with the other one
then you can add up

Answer 5

i was adding first which was why i got confused but thank you!!

Answer 6

yw