Question

2(6z-1)-5(z+2)=4(z+1)
The Solution is Z= ?

Answer 1

Expand the terms and simplify first:
2(6z-1) = 12z - 2
-5(z+2) = -5z - 10
4(z+1) = 4z + 4
So 12z - 2 -5z - 10 = 4z + 4
7z - 12 = 4z + 4
Subtract 4z from both sides
3z - 12 = 0 + 4
Add 12 to both sides
3z = 16
divide both sides by 3
z = 16/3

Answer 2

Let me put z = 16/3 back in the equation to see if it works...

Answer 3

yes z = 16/3 works.