Question

Can someone explain this to me?

Answer 1

we have got modulus function in denominator its k... just find right hand or left hand limit
and that would be your answer..

but remember for left hand limit we have x<4 so question will be like this

\[\lim_{x \rightarrow 4^-} (x-4)^3/(4-x)\]

and for right hand limit

\[\lim_{x \rightarrow 4^+} (x-4)^3/-(4-x)\]

Answer 2

\[\frac{(x-4)^3}{4-x}\text{=}-x^2+8 x-16 \]