Question

calc bc. integration prob?

postin**

Answer 1

sorry

Answer 2

\[f(x)=\begin{cases}
x & \text{ if } x \le 0\\
x+1 & \text{ if } x>0
\end{cases}\]
Find:
\[\int_{-2}^1xf(x)dx\]

Maybe
\[\int_{-2}^1xf(x)dx\]\[=\int_{-2}^0 x(x)dx+\int_0^1x(x+1)dx\]\[=...\]

Answer 3

ohh yea! duh should of drawn it out first. i see how you divided it