Question

The equation of a line is . What is the equation of the line that is parallel to the first line and passes through (4, –2)?

Answer 1

So what's the equation for first line?

Answer 2

y=1/4x-2

Answer 3

so slope of first line is the coefficient of x i.e. 1/4
and as it is parellal to the required line. slopes would be same.
required eqn is,
(y-y1)=m(x-x1)
where m=slope and(x1,y1) is the given point
(y-(-2))=1/4(x-4)
4(y+2)=x-4
4y+8=x-4
4y-x=-4-8
4y-x=-12