Question

Solve the system by elimination.
-2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5

Answer 1

-2x+2y+3z=0
-(-2x-y+z=-3)

3y+2z=3

2x+3y+3z=5
-2x+2y+3z=0

5y+6z=5

3(3y+2z=3)
-(5y+6z=5)

4y=-2
y=-1/2

5(-1/2)+6z=5
-5/2+6z=5
6z=2 1/2
z=5/2

Answer 2

I dont have time to finish the explanation but you understand the basic concept just finis solving for z then plug z and y into an equation with x to find x