Question

Factor completely 3x^3 + 12x^2 + 18x.

x^2 + 4x + 6

3(x^3 + 4x^2 + 6x)

3x(x^2 + 4x + 6)

x(3x^2 + 12x + 18)

Answer 1

@ganeshie8

Answer 2

GCFs...

3, and x?

Answer 3

so 3x(x^2 + 9x^1 + 18)?

Answer 4

you're right about GCFs

Answer 5

check ur second step again, 9 and 18 are not correct.

Answer 6

3x(x^2 + 9x^1 + 15)?

Answer 7

3x^3 + 12x^2 + 18x

factor out GCF 3x

3x(x^3 + 4x + 6)

Answer 8

12/3 = 4

18/3 = 6

ok ?

Answer 9

oh my bad i was subtracting lol

Answer 10

3x(x^2 + 4x^1 + 6)

Answer 11

now that weird formula lol

Answer 12

(a+b)2=a2+2ab+b2
(a−b)2=a2−2ab+b2
a2−b2=(a+b)(a−b)

Answer 13

knw what, we're done !
look at ur options :)

Answer 14

oh lol

Answer 15

thanks :D

Answer 16

yw (: