Mathematics
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OpenStudy (anonymous):
Which of the following is a factor of 2x^4 + 22x^3 + 60x^2?
2x^3
x^4
x + 4
x + 5
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OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
GCF...
2 and x^2
OpenStudy (anonymous):
sooo...
2x^4 + 22x^3 + 60x^2
2 and x^2
2x^2(x^2 + 11x^1 + 30)
ganeshie8 (ganeshie8):
perfect!
OpenStudy (anonymous):
lol weird formula time xD
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ganeshie8 (ganeshie8):
next we need to factor x^2 + 11x + 30
ganeshie8 (ganeshie8):
formulas wont work this time :o
OpenStudy (anonymous):
o_O
OpenStudy (anonymous):
lol what do we do then
ganeshie8 (ganeshie8):
this is a new method,
see if u can follow it :-
first, we pick two numbers \(a\), \(b\) such that :-
\(a*b\) = 30
\(a+b\) = 11
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ganeshie8 (ganeshie8):
can u tell me the two numbers ?
OpenStudy (anonymous):
10 * 3 = 30
5 + 6 = 11
ganeshie8 (ganeshie8):
noo, both shud be same
ganeshie8 (ganeshie8):
a*b = 30
and, same
a+b = 11
ganeshie8 (ganeshie8):
like that...
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ganeshie8 (ganeshie8):
5*6 = 30
5+6 = 11
ganeshie8 (ganeshie8):
so, 5 and 6 are our numbers, ok
OpenStudy (anonymous):
alright I got it
ganeshie8 (ganeshie8):
next :-
2x^2(x^2 + \(11x\) + 30)
2x^2(x^2 + \(5x + 6x\) + 30)
ganeshie8 (ganeshie8):
fine ?
i just wrote 11x as 5x+6x
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OpenStudy (anonymous):
yeah im following ya
ganeshie8 (ganeshie8):
2x^2(x^2 + \(11x\) + 30)
2x^2(x^2 + \(5x+6x\) + 30)
-------- --------
ganeshie8 (ganeshie8):
factor those two separately
ganeshie8 (ganeshie8):
2x^2(x^2 + \(11x\) + 30)
2x^2(x^2 + \(5x+6x\) + 30)
-------- --------
2x^2(x(x+\(5\))+\(6\)(x + 5))
2x^2(x+\(5\))(x + \(6\))
ganeshie8 (ganeshie8):
take it slow... if it doesnt make fully sense its okay, you need to practice 2-3 problems to see how the method works
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OpenStudy (anonymous):
Yeah i understand it a bit, thanks :)
ganeshie8 (ganeshie8):
good to hear :)