Question

can someone help me I need The standard form equation of my conic below PLEASE HELP WILL GIVE MEDAL

Answer 1

@wio have any idea?

Answer 2

The equation for a sphere in R³ represented in rectangular (Cartesian) coordinates with radius r and center at (x₀, y₀, z₀), is (x - x₀)² + (y - y₀)² + (z - z₀)² = r². So the equation of the sphere of radius 2√6 and center (4, -2, 1) is (x - 4)² + (y - (-2))² + (z - 1)² = (2√6)² which simplifies to (x - 4)² + (y + 2)² + (z - 1)² = 24.

Answer 3

like I understand that but like I really don't get how I can write a equation for a picture!

Answer 4

(x₀, y₀, z₀), is (x - x₀)² + (y - y₀)² + (z - z₀)² = r²

Answer 5

so that's all I put formy pic is that?

Answer 6

I dont know? What class is this in.

Answer 7

pre calc honors

Answer 8

LOL. what grade are you in?

Answer 9

12th

Answer 10

Me to...but im not taking pre calc.

Answer 11

what are ya taking?

Answer 12

Do you take online?

Answer 13

Can you please help me?:

http://openstudy.com/updates/526082dae4b0c78c62eade37

Answer 14

@amistre64 have any idea

Answer 15

the equation of a sphere ... center it wherever you want it centered; id pick the origin

Answer 16

the general form of a conic at the origin, if memory serves:

Ax^2 +By^2 +Cz^2 +Dxy +Exz +Fyz +Gxyz +H

maybe

Answer 17

so like what i dont get is how to do it for a picture

Answer 18

if the picture is 2 dimensional, just determine the radius you want for the ball, and apply it to a circle ...

x^2 + y^2 = r^2

Answer 19

if you have to overlay a grid, then approximate the values

Answer 20

so could i just say 4

Answer 21

@amistre64

Answer 22

4^2 + 4^2= 6^2>