Question

find the two numbers whose differences is 4 and the difference of their squares is 88

Answer 1

@luhan

Let the numbers be x and y.

x - y = 4 because the two numbers differ by 4

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the difference of their squares is 88

x^2 - y^2 = 88

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Then, solve these two equations simultaneously:

x - y = 4

x^2 - y^2 = 88

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If you are allowed to use technology in your work,

go here:
http://www.wolframalpha.com/input/?i=%28x+-+y+%3D+4%29+and+%28x%5E2+-+y%5E2+%3D+88%29

If not, use substitution to crank out the answers by hand.