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Mathematics
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Eulers Method
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Dy/dx = y/x + x^2 - 2 Needed in the form dy/dx = f (x, y)
do you have an initial point?
H = 0.2 Y (1.5)
so, step is .2 , starting x is 1.5; what is the Y value?
Y (1) = 3
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so initial x is 1, and initial y is 3 other than the rote repetition of it all, what are you needing help with?
I need to get the above equation in dy/dx = f (x, y)
Y (1) = 3
Y' is already defined Xn+1 = Xn + h Yn+1 = Yn + Y'h
The equation is already correct?
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you posted: Dy/dx = y/x + x^2 - 2 this is already in dy/dx = f(x,y) format .... not too sure what it came from tho
So I can proceed?
what did you start with? did you arrange it into this dy/dx from something else?
No, was just given this. I will try it now, thanks!
good luck ;)
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