Factor 10x2 - 5x
A. 5x(2 - x)
B. 5x(2x - 1)
C. 5( 2x2 + x)
D. 2(5x2 + x)
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OpenStudy (nirmalnema):
b option is correct
OpenStudy (nirmalnema):
u can take out 5x common
so u will get 5x(2x-1)
OpenStudy (nirmalnema):
@chulie_isobel did you understand
OpenStudy (anonymous):
kinda.... is it still the same tho? bc i forgot to raise the 2 up
OpenStudy (nirmalnema):
yaa 2x*5x=10x^2
like 2*2 = (2)^2
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OpenStudy (anonymous):
so its still b?
OpenStudy (nirmalnema):
yup..
OpenStudy (anonymous):
do u think u could help me with some more problems?
OpenStudy (nirmalnema):
yup sure i will try
OpenStudy (anonymous):
thanks.. okay so heres the next oone....
Factor out the common monomial: 33x5 – 6x4 + 18x3
A. 3x3 (11x2 + 2x + 6)
B. 3x3 (11x2 - 2x - 6)
C. 3x3 (11x3 - 2x + 6)
D. 3x3 (11x2 - 2x + 6)
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OpenStudy (texaschic101):
33x^5 - 6x^4 + 18x^3
3x^3 (11x^2 - 2x + 6)
OpenStudy (nirmalnema):
D option is correct
OpenStudy (nirmalnema):
\[3x^3 (11x^2 - 2x + 6)\]
OpenStudy (anonymous):
thanks :).. my next one is:
Factor: z^2 - 2z
A. z(z + 2)
B. (z - 1)(z - 2)
C. z^2
D. z(z - 2)
OpenStudy (texaschic101):
factor out the z
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OpenStudy (nirmalnema):
D again
OpenStudy (nirmalnema):
z(z-2)
so u get z^2-2z
OpenStudy (anonymous):
so can u explain to me hpw to do this? i dont get it at all. the whole factoring thang...
OpenStudy (nirmalnema):
take out z (common term) from both the terms of binomial
OpenStudy (nirmalnema):
@chulie_isobel do u get it
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