Mathematics
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OpenStudy (anonymous):
What are the solutions of the equation: z2 - 12z + 36 = 0?
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OpenStudy (anonymous):
what you mean is you want to find the value of z correct?
OpenStudy (anonymous):
umm yes i think so.
OpenStudy (anonymous):
Here are the answers.
A. -6, 6
B. 6, 6
C. 6, -6
D. -6, -6
OpenStudy (anonymous):
ok then what do you think should be our first step?
OpenStudy (anonymous):
ok so you are looking for a point. based on the answer choices
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OpenStudy (anonymous):
z^2+12z+36 =(z+6)(z+6)
OpenStudy (anonymous):
Umm Im not sure.if i am or not.But the answer i got was b, but i dont know if its correct or not.
OpenStudy (anonymous):
ok yes this is a quadratic equation you didnt put the z^2 in the first equation.
OpenStudy (anonymous):
do you know how to factor?
OpenStudy (anonymous):
Haha lol how do you know?
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OpenStudy (anonymous):
not sure.
OpenStudy (anonymous):
not sure how to factor or not sure if im right about what it is?
OpenStudy (anonymous):
Im confused.
OpenStudy (anonymous):
ok what are you confused about?
OpenStudy (anonymous):
Wait my equation is correct. im just not sure on the answer.
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OpenStudy (anonymous):
Solution (z+6)(z+6) = z=-6 z= -6 This should be your answer D. -6,-6
OpenStudy (anonymous):
Ok thanks. Im closing.
OpenStudy (anonymous):
@jmartinez44 @Kenziehulse im sorry but d is not correct
OpenStudy (anonymous):
Ok then what do you think it is?
OpenStudy (anonymous):
It is not?
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OpenStudy (anonymous):
z^2-12z+36=0
(x-6)(x-6)
(6,6)
the b variable is negative
B is your answer
OpenStudy (anonymous):
My bad I didn't see the -12z I'm very sorry
OpenStudy (anonymous):
its ok jmartinez44
OpenStudy (anonymous):
so my answer choice b was correct?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
Thanks now im closing.
OpenStudy (anonymous):
I opened up another.