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identify the vertex, axis of symmetry, maximum value, and range of y=3x^2-6x+2
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vertex is (1,-1)
so then the axis of symmetry would be x=1
what is the maximum value, and range
wait i think you are wrong about the vertex. the form is y=ax^2+bx+c and the c term is the y-intercept
I graphed it and that is what I got for the vertex
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im sorry you are right just because it intercepts the y-ax at +2 doesnt mean that is where the vertex is. my mistake
well i did the maximum function on my graphing calculator and it gave me the maximum of (0,2) does that sound right to you?
This is what I got then the axis of symmetry would be x=1 minimum value y=-1 range is... range y>1-
ok what about the maximum
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