Question

What is the turning point of y= x^2+x-2

Answer 1

Find the vertex

Answer 2

if you want the vertex?
y=x^2+x-2
y=(x^2+x)-2
y=(x^2+x+0.25-0.25)-2
move the -0.25 out of the brackets:
y= (x^2+x+0.25)-2.25
factor:
y=(x+0.5)^2 -2.25
vertex: (-0.5,-2.25)