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Mathematics 13 Online
OpenStudy (anonymous):

factor (27v^3)+64

OpenStudy (anonymous):

use a^3 +b^3= (a+b)(a^2 -ab +b^2)

OpenStudy (anonymous):

here we have (3v)^3+ 64 =(3v^3)+ (4)^3 so we may assume a = 3v and b as 4

OpenStudy (anonymous):

ok working..

OpenStudy (anonymous):

(3v+4)((9v^2)-12v+16)

OpenStudy (anonymous):

can it be factored more?

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