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Mathematics 18 Online
OpenStudy (usukidoll):

Suppose that L is a linear differential operator and L(cosx) doesn't equal to 0. and L(sinx) doesn't equal to 0. Prove that the equation Ly=cosx has a solution of the form A cosx + B sinx

OpenStudy (usukidoll):

so it must have a complex root to even have such a format.

OpenStudy (usukidoll):

since e^rx(cos x + sin x )

OpenStudy (usukidoll):

@ParthKohli

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