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OpenStudy (usukidoll):
Suppose that L is a linear differential operator and L(cosx) doesn't equal to 0. and L(sinx) doesn't equal to 0. Prove that the equation Ly=cosx has a solution of the form A cosx + B sinx
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OpenStudy (usukidoll):
so it must have a complex root to even have such a format.
OpenStudy (usukidoll):
since e^rx(cos x + sin x )
OpenStudy (usukidoll):
@ParthKohli
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